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Festus s t bangura
Answers (1)
X: variable random So 8 brown socks plus 4 blue socks in the drawer=12 socks Let assume that P(no brown socks) means P(X=0)=(4/12)³ must be equal to 1/27 P(X=1)=[8/12(4/12)² +(4/12)²8/12 +(4/12×8/12×4/12)]=6/27 P(X=2)= 3(8/12×8/12×4/12) =4/9 P(X=3)