Essan

Solve xy' + y + y^2 = 0 for y(1) = 2 --------- I isolated y' such that: y' = (-y^2-y)/x But I'm not sure what to substitute from here I could do v = -y^2- y and v' = -2yy' - y' but I'm not sure this would help

Show that {e^x, e^(x+2)} are linearly independent -------------------- Let C1e^x + C2e^(x+2) = 0 for x = ln1: C1(1) + C2e^2 = 0, so C1 = -C2e^2 for x = 0: C1 + C2e^2 = 0 substituting gives: -C2e^2 + C2e^2 = 0 Does this suffice? Is there a way to get C1 =...

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