Ask a New Question
Search
Questions and answers by
Eric Uwanyagasani kappy
Answers (2)
let x be width and y be length ,and as we know perimeter of rectangle=2(length+width) so 2(x+y)=100 x+y=50 , x=50-y area=length*width area=xy=(50-y)y area=50y-y^2 dA/dy=0 for min or max dA/dy=50-2y=0 y=25 x=25
let x be width and y be length ,and as we know perimeter of rectangle=2(length+widith) so 2(x+y)=100 x+y=50 , x=50-y area=length*width area=xy=(50-y)y area=50y-y^2 dA/dy=0 for min or max dA/dy=50-2x=0 y=25 x=25
