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Ekta gupta
Answers (2)
Internal diameter =2.8cm Radius=1.4cm Thickness =1mm=0.1cm External radius =1.4cm+0.1cm=1.5cm (V1) volume of hollow pipe =pie×h×(R+r)(R-r)=(22÷7 )×h×2.9×0.1=0.9hcm^2 (V) volume of rod with same length=pie×r^2×h=(22÷7)×r^2×h V1=V
Its answer is 1.08 cm diameter
