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Editorial - Reiny

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work backwards ... f''(x) = 10 then f'(x) = 10x + c we know that when x = 4, f'(4) = 0 0 = 10(4) + c c=-40 so f'(x) = 10x - 40 finally , f(x) = 5x^2 - 40x + k we know that when x =2, f(4) = 4 carry on
I find it alarming that so many students appear to be in getting their education from on-line charter "schools" like Connection Academy. Many of the problems posted are of such a simplistic nature, that most capable students would just have to know. If you

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