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Dr Greg
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Moles=concentration x Volume (n=cv) 0.5 x 250 divided by 1000 0.5/1 x 250/1000= 0.125 Calculate the Molar MAss of anhydrous Calcium Carbonate Na2 = (2 x 22.98) + C (1 x 12.01) + O3 (3 x 15.99) = 105.987 g/Mol m (MASS)= 0.125 x 105.987 = 13.248 g :)
