Divya S

This page lists questions and answers that were posted by visitors named Divya S.

Questions

The following questions were asked by visitors named Divya S.

Answers

The following answers were posted by visitors named Divya S.

Given, a = 2 m/s^2 t = 10 s u =0(Initial speed) v = ? (Final speed) By the equation v = u + at v = 0 + 2*10 = 0 + 20 = 20 m/s Therefore the speed 2 sec after it was dropped is 20 m/s