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Divya S

Answers (1)

Given, a = 2 m/s^2 t = 10 s u =0(Initial speed) v = ? (Final speed) By the equation v = u + at v = 0 + 2*10 = 0 + 20 = 20 m/s Therefore the speed 2 sec after it was dropped is 20 m/s

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