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How many grams of NaOH(Mr 40) must be added to 100 ml of 0.1M H3PO4 to create phosphate buffer, pH 7.0?
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100 ml * 0.1 M= 10 mmole 7.0 = 7.21 + log HPO4^-2/ 10- HPO4^-2 HPO4^-2 = 1.27M how do i get to grams Right, Dr.Bob?
