Desz

I'm getting a little confused..would you mind telling me how you would solve this problem? Thank you.

I actually did find 92 for my molar mass, but for the molar mass of the molecular formula I found 1666.67 and so I did 1666.67/92 which equals to 18. I then multiplied my empirical formula, C3H8O3 by 18 and got the answer C54H144O54.I found the molar mass...

I actually did all that already.. Do you want me to post how I did it? And for the 2.00 g, don't I need the mass of the CHO compound and divide it by the moles to get the MM of the molecular formula? And then I do MM of molecular/MM of empirical to get th...

I found C3H8O3for my empirical formula, that's where I got the 92.

Ohhhh I get it now.. Thank you so much!!! One last question, how would you calculate the 92 from the freezing point data? I understand everything now, but just not that one point.

Ohhhhhh I understand now.. I thought that I did the freezing point wrong since you said I got the wrong answer.. But I understand now. THANK YOU SO MUCH! Sorry for taking up so much of your time!