Debele Bedada

This page lists questions and answers that were posted by visitors named Debele Bedada.

Questions

The following questions were asked by visitors named Debele Bedada.

Answers

The following answers were posted by visitors named Debele Bedada.

Solution. a)v=u+at =30+3*10 =60m/s b)s=vt+1/2at^2 =30*10+0.5*3*10*10 =450m c)F=ma =1000kg*3m/s^2 =3000N d)P=mv =1000kg*30m/s =30000unit e)KE=1/2mv^2 =0.5*1000kg*30^2 =40000J