David D.

The electric field strength 6.0 cm from a very long charged wire is 1700 N/C. What is the electric field strength 10.0 cm from the wire?

Two 10 cm diameter charged rings face each other, 20 cm apart. The left ring is charged to -20 nC and the right ring is charged to +20 nC.

Two 10 cm diameter charged rings face each other, 20 cm apart. The left ring is charged to -20 nC and the right ring is charged to +20 nC. What is the force on a 1.2 nC charge placed at the midpoint? I have already calculated the electric field between th...

The electric flux through the surface shown in Figure Ex27.10 is 15.0 Nm2/C, and the electric field makes an angle α = 70° with the surface. What is the electric field strength? The surface is a 10cm by 10cm square.

A long, thin straight wire with linear charge density -λ runs down the center of a thin, hollow metal cylinder of radius R. The cylinder has a net linear charge density 2λ. Assume λ is positive. Find expressions for the electric field at the following loc...

A long, thin straight wire with linear charge density -λ runs down the center of a thin, hollow metal cylinder of radius R. The cylinder has a net linear charge density 2λ. Assume λ is positive. Find expressions for the electric field at the following loc...

A balloon contains 7.2 L of He. Th e pressure is reduced to 2.00 atm and the balloon expands to occupy a volume of 25.1 L. What was the initial pressure exerted on the balloon? I got 0.57 ml, but the answer says 7.0 ml. I am not sure if my answer is wrong...

A gas has a volume of 2.5 L at 25 degrees Celsius and 742 mmHg. Calculate the volume at 55 degrees celsius and 825 mmHg. I got 2.5 L again. Is that possible?

The radius of this circle is one unit. Find the exact lengths of the legs in the right triangle if: Sides a is twice as long as side b. And Sides b is twice as long as side a. Basically the hypotenuse of this triangle is 1 and we are trying to use the pyt...

1020 N/C

Ke = .5mv^2 so the ke is .5(26)(8.4^2)= 917.28

Sorry What is the force Fvec on a 1.2 nC charge placed at the midpoint?

Thank you. I didn't know I could do that, but it did give me the right answer.

24-20 gives the number of yards remaining. Then multiply this by 3 because there are three feet in a yard. This results in 12 feet.

Volume 1 = 54.2 L Pressure 1 = 1150 mmHg Volume 2 = ? Pressure 2 = 3450 mmHg 54.2 L * (1150/3450) = 18 L 1150/3450 because volume should get smaller since pressure is increasing

5/5-2/5 = 3/5 1/5 + 1/5 + 1/5 = 3/5 0.2 + 0.2 + 0.2 = 0.6 So 1/3 would be equal to 0.2 which means that after the farmer gave away 1/3 of his cattle he would have 40% left or 2/5.

he answered 94% correctly if you have 94/100 then you just need to put down 94 and then the percent sign after % represents 100 (note the 2 zeros in the percent sign)