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David D.
Questions (9)
The radius of this circle is one unit.
Find the exact lengths of the legs in the right triangle if: Sides a is twice as long as
2 answers
628 views
A gas has a volume of 2.5 L at 25 degrees Celsius and 742 mmHg. Calculate the volume at 55 degrees celsius and 825 mmHg.
I got
3 answers
553 views
A balloon contains 7.2 L of He. Th
e pressure is reduced to 2.00 atm and the balloon expands to occupy a volume of 25.1 L. What
3 answers
1,668 views
A long, thin straight wire with linear charge density -λ runs down the center of a thin, hollow metal cylinder of radius R. The
3 answers
2,714 views
A long, thin straight wire with linear charge density -λ runs down the center of a thin, hollow metal cylinder of radius R. The
1 answer
1,309 views
The electric flux through the surface shown in Figure Ex27.10 is 15.0 Nm2/C, and the electric field makes an angle α = 70°
1 answer
873 views
Two 10 cm diameter charged rings face each other, 20 cm apart. The left ring is charged to -20 nC and the right ring is charged
5 answers
3,013 views
Two 10 cm diameter charged rings face each other, 20 cm apart. The left ring is charged to -20 nC and the right ring is charged
3 answers
1,198 views
The electric field strength 6.0 cm from a very long charged wire is 1700 N/C. What is the electric field strength 10.0 cm from
3 answers
1,096 views
Answers (8)
he answered 94% correctly if you have 94/100 then you just need to put down 94 and then the percent sign after % represents 100 (note the 2 zeros in the percent sign)
5/5-2/5 = 3/5 1/5 + 1/5 + 1/5 = 3/5 0.2 + 0.2 + 0.2 = 0.6 So 1/3 would be equal to 0.2 which means that after the farmer gave away 1/3 of his cattle he would have 40% left or 2/5.
Volume 1 = 54.2 L Pressure 1 = 1150 mmHg Volume 2 = ? Pressure 2 = 3450 mmHg 54.2 L * (1150/3450) = 18 L 1150/3450 because volume should get smaller since pressure is increasing
24-20 gives the number of yards remaining. Then multiply this by 3 because there are three feet in a yard. This results in 12 feet.
Thank you. I didn't know I could do that, but it did give me the right answer.
Sorry What is the force Fvec on a 1.2 nC charge placed at the midpoint?
Ke = .5mv^2 so the ke is .5(26)(8.4^2)= 917.28
1020 N/C
