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Damon typo
Answers (4)
Q2 = [6*10^-6 Coulombs + Q1] because attracting one must be + and the other - .9 = k Q1Q2/0.40^2 .9*.16 = 9*10^9 (Q1)(-6*10^-6+Q1) 16*10^-12 = -6*10^-6 Q1 +Q1^2 Q1 ^2 - 6*10^-6 Q1 - 16 *10^-12 = 0 pretend it is Q1^2 - 6 Q1 - 16 =0 (Q1 - 8)(Q1+2) = 0 so one
yes, the plane determined by any great circle around a sphere passes through the center.
R(x)= 40x^2 { e^ ???? } -0.4x +30
I typed 73 instead of 273
