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Please verify my answer.
Find the average value of the function f(x) = x√(1+2x) on the interval [0,4] Favg = 1/(b-a) ∫ from a
3 answers
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Using the Fundamental theorem of Calculus find the derivative of
F(x) = sec(3x) + ∫ [e^-(t^(2))] Integral from ( 0 to tan(3x) )
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Alright so, = 1/(4-0) ∫ x√(1+2x) dx u = 1+2x du = 2 dx 1/2 du = x = 1/4 [ (u-1)/2 (u)^(1/2) (2)] du = 1/4 [ u^(3/2) - u^(1/2)] du = 1/4 [ (2/5)(1+2x)^(5/2) - (2/3)(1+2x)^(3/2)] = (1/10)(1+2x)^(5/2) - (1/6)(1+2x)^(3/2) + C Then, [ ∫b -∫a] 198/10 +
density (p)= m/V V= m/p V Al = ? m Al = 2000g p Al = 2.70g/cm3 Plug info into this equation: V= m/p and you should get 740.74 cm3 as the volume.
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