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Christena

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Solve for p.3+|1+p|=123+|1+p|=12 A. p = 8 or p=−10p=−10 B. p = 14 or p=−16p=−16 C. p = 10 or p=−10p=−10 D. p = 8 or
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The width of a rectangle is 8 cm less than its length. The perimeter of the rectangle is 52 cm.What is the width of the
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2. 1,188 views