ChrisZZ

Okay, the reaction is this: Naphthalene + HNO3 ---> NitroNapthalene The limiting reagent is Naphthalene The excess is the nitric acid The equation is 1:1 balanced as far as I know 3 g of Nap used in the experiment x 1mol/128.17 g/mol = .023 mol Nap 12.69...