Chiman

This page lists questions and answers that were posted by visitors named Chiman.

Questions

The following questions were asked by visitors named Chiman.

Answers

The following answers were posted by visitors named Chiman.

HF(aq)+H2O(l)<->H3O+ + F- 0.027 M XM XM mol of HF in equilibrium= 0.0300 -0.0270= 0.003 mol [H3O+] = [F-] = mol / V = 3 * 10-3 mol / 1.0 L = 3 * 10-3 M 3. Ka = [ H3O+] [F-] / [HF]  = 3 * 10-3 X 3 * 10-3 / 2.7 * 10-1 = 3.3 * 10-4
9 years ago