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Chillymcfreeze
Answers (1)
In order to solve this, you need to relate the ratio of kJ of heat and the moles of Ca(OH)2 in the reaction, to an unknown kJ of heat and moles of Ca(OH)2 in 273kg. 1 mole of Ca(OH)2 = 74.09g Set up a proportion: 65.2kJ/74.09g = ??kJ/273000g Then cross
