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Chemman7
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Since 1 g of copper is deposited, that is 1/63.55 = 0.016 mol of Cu approximately. Since the equation is CuBr2 -> Cu2+ + 2 Br- the mol ratio is 2 to 1. 2:1 Br:Cu x:0.16 x=0.0315 mols of Br. since m = nM, m= 0.0315 x 79.9 (Molar mass of Br) m=2.5145 g of Br
