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ChemJunkie
Answers (1)
dGo = -nFEo where n = 6 F = 96,485 and Eo = cathode - anode = (+1.498) - (-0.26) = 1.758 So, (-6)(96,485)(1.758) = -1,017,720 J or -1017.72 KJ (Make sure you divide by 1,000 to convert from J to KJ if the question asks for the answer in KJ)
