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ChemHurts
Questions (3)
For the titration of 25.00 mL of 0.150 M HCl with 0.250 M NaoH, calculate (a) the initial pH; (b) the pH when neutralization is
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The PH of an aqueous solution of NaCN is 10.38. What is [CN-] in this solution?
3 answers
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If 535 Ml of gaseous HCL, at 26.5 degrees Celsius and 747mm Hg, is dissolved in enough water to prepare 625 ml of solution, what
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Answers (3)
Ok Thanks a lot guys.
I determined the number of millimoles of HCl initially to be 3.75. How do I determine how much moles of NaOH are added at 50% completion for example because the volume isn't given.
Sorry for double posting but I got a solution of [CN-] = 0.0036 M. Can someone verify if that is right.
