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8.3 grams of NaCl and 3 grams of KBr were dissolved in 47 mL of water. What is the mole fraction of KBr in the solution?
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Answers (4)
so, i got 6.82 moles of water and plug that in and get .00361, right?
d=m/v=47g/47mL because 1g water = 1mL water moles= dv/m=1(47)/47=1
nevermind,i got .02...did i do this correctly??
i got 1.2 but i don't think i did it right. below is my work: 3g(1mole/199g)=.03moles KBr .03/(1moleH2O+.03molesKBr+.14moles NaCl)= 1.2 moles H2O = (1(47))/47=1
