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Chau Phan
Answers (1)
68.57Km/Hr let X = distance; t1 = x/80*2; t2 =60*2; t = x/ V average. t1 + t2 = t = x / V average (x / 160) +(x / 130)= x / V average x(1/160 + 1/120) = x /V average x( .014583333) x/V average ( .014583333)= 1/ V average V average = 1/ ( .014583333) V