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_______g of MnSO4 H2O are needed to prepare a solution of 100.00mL of 0.100 M MnSO4. Thank You

Select all ionic compounds in which the number of anions present is two. carbon dioxide X manganese(II) hydroxide mercury(II) carbonate X mercury(II) phosphate ammonia sulfur dioxide Hello, I know manganese(II) hydroxide mercury(II) phosphate both have tw...

A 3.29 m solution of the solute H2O dissolved in the solvent acetone is available. Calculate the mass ( kg ) of the solution that must be taken to obtain 26.70 mol of H2O. m= molality I have no idea how to approach this problem, I'm not interesting in get...

tried using M1V1=M2V2 but without sucess

oh thanks I get it now..

Okay thank you that makes a lot more sense!

I found another post on this site, which explains a similar problem. :)

Thank you! I got the correct answer.

This makes more sense, but your first step is a little confusing. when I do 26.70 x 18.015 g H2O/mol I get 481.005 but when I do: 3.29 m x 18.015 g H2O/mol then I get your ans: 50.269 g H20

And I'm a little unsure as to why after you find the mass of the solution 1059.269 you find how many g of H20 are in 1000 g of that soln. Why can't we just use the 1058.269 g? Was it to get the perfect 1000g (1kg) or was that unnecessary?

In regards to your latest post, I meant the very first step, not the step you did to check the answer. I'm assuming the first line is a typo?

its just the 2nd and 4th one

Ohhhhh That makes so much more sense. I didn't fully understand what the problem was asking. Thank you so very much =)

N-methylbutanamide