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ChEm
Questions (6)
A 3.29 m solution of the solute H2O dissolved in the solvent acetone is available. Calculate the mass ( kg ) of the solution
12 answers
1,188 views
Select all ionic compounds in which the number of anions present is two.
carbon dioxide X manganese(II) hydroxide mercury(II)
2 answers
864 views
The longer the hydrogen bond, do the Intermolecular Forces increase or decrease.
So if molecule A has a H-bond with a length of
0 answers
958 views
A stock solution was prepared by dissolving exactly 0.4000 g of pure ASA (180.16 g/mol)
in 10.00 mL of NaOH and heating the
2 answers
1,452 views
A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude
and direction of the
0 answers
761 views
_______g of MnSO4 H2O are needed to prepare a solution of 100.00mL of 0.100 M MnSO4.
Thank You
3 answers
1,311 views
Answers (11)
N-methylbutanamide
Ohhhhh That makes so much more sense. I didn't fully understand what the problem was asking. Thank you so very much =)
its just the 2nd and 4th one
In regards to your latest post, I meant the very first step, not the step you did to check the answer. I'm assuming the first line is a typo?
And I'm a little unsure as to why after you find the mass of the solution 1059.269 you find how many g of H20 are in 1000 g of that soln. Why can't we just use the 1058.269 g? Was it to get the perfect 1000g (1kg) or was that unnecessary?
This makes more sense, but your first step is a little confusing. when I do 26.70 x 18.015 g H2O/mol I get 481.005 but when I do: 3.29 m x 18.015 g H2O/mol then I get your ans: 50.269 g H20
Thank you! I got the correct answer.
I found another post on this site, which explains a similar problem. :)
Okay thank you that makes a lot more sense!
oh thanks I get it now..
tried using M1V1=M2V2 but without sucess
