Carmieee

A ball is thrown up in the air with an initial velocity of 15m/s from a 17m high platform Find Maximum height reached by the ball Time of flight if the ball is catched Time of flight when it strike the ground Velocity when it returns to the hand Velocity...

a projectile is launched from a cliff 100m above level ground with a launch velocity angle of 20 degrees above the horizontal What is the horizontal displacement and time upon impact And the max height it traveled

What happens if a solid is dissolved in a boiling point or freezing point?

What is the intermolecular force in CO? ASIDE FROM LONDON DISPERSION FORCE ARE THERE ION DIPOLE FORCE IN CO OR NONE?

Find center on y=1/3x+6, tangent to y=x+20(11;9)

My max height results into 28.47m I used the equation Vf^2=Vo^2+2gdy In the time of flight when it reaches the hand will be 1.53s Using the eqn Gt=Vf-Vo Time as it strikes the ground will be 3.94s Using the eqn dy=Vot+.5(-9.81m/s^2)t^2

May I ask if t= time of flight going up and t"=time of flight going down

Can I really solve this without the magnitude of the hand from the ground which considered to be the reference point?

I think it lacks information when it comes to solving for time and final velocity as it reaches the hand

I got same value for t' and t is it possible? And if I'm about to add it it will be t"

Another question is in finding the final velocity. Using the gt=vf-vo Will the values depend on the time fall as it reach the coin and is it the initial velocity in the top also 0m/s?

Okay I got it now. Thank you so much sir! :)

the given is 0.33x+16, tangent to y=x+20(11,9)