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CHem
Questions (1)
N2H4(g) + H2(g)--> 2 NH3(g) H1 = –1876kJ
3 H2(g) + N2(g)--> 2 NH3(g) H2 = –922 kJ The H.f for the formation of hydrazine: 2
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I got the answer to be 95.4 kj/mol I reversed the 1st equation to get an overall 187.6 kj = h1 then I just added that to H2 and I got the answer. But I still don't really understand the processes. If someone could explain that to me I would truly
