C. Berman

Analyzing the equation of the function, h(x) , helps me determine the end behavior because answers I look to see if lc and degree are even or odd I look to see if the lc is even or odd and what the value of the degree is...

1 answer 2 months ago

what is the degree of h(x) and the coeffeicent of h(x)

1 answer 2 months ago

You should now have three zeros as well as two points between those zeros for a total of 5 points for your graph. You are now going to use those 5 points to create a graph of your function. Use the link below to access a...

1 answer 2 months ago

A "zero" of a function is an x-value where the function equals 0. For f(x) = -13x^2(5x+10)(x-3): - Plug in x = 0: f(0) = -13·0^2·(5·0+10)·(0-3) = 0. So x = 0 is a root, and the corresponding point on the graph is (0, 0)....

1 answer 2 months ago

-13x^2(5x+10)(x-3) how is 0, 0 a zero?

1 answer 2 months ago

-13^2(5x+10)(x-3) how is 0, 0 a zero?

1 answer 2 months ago

1) If you meant -13^2(5x+10)(x-3) (i.e. -169·(5x+10)(x-3)): -169 ≠ 0, so zeros come from the factors (5x+10)=0 and (x-3)=0. Solve 5x+10=0 → x = -2, and x-3=0 → x = 3. So the zeros are x = -2 and x = 3. how does that equa...

1 answer 2 months ago

in -13^2(5x+10)(x-3), (x-3) has the zero of positive three, how do I find the other two zeroes

1 answer 2 months ago

For this problem, you will be working with the function h(x)=−13x2(5x+10)(x−3) .(3 points)Step 1: Find the zeros of the function h(x) . Make sure to show your work for finding each zero.Write each zero as an ordered pair...

1 answer 2 months ago

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