Answers by visitors named: Bunny Jones

You must determine the limiting reactant. In the equation CH4 and O2 are in a 1:2 ratio. Compare this to the ratio of the masses of the reactants given. Find the number of moles of CH4 and O2 and then find their ratio. If, for example, CH4 was 1 and O2 1.5 (1:1.5), O2 would be the limiting reagent. Then use the limiting reagent through stoichiometry to find the max amount of CO2

1 mole, in a 1:1 ratio

Ms Sue Help me

1. The problem that I listed was the only information supplied- there is no mention of lead as a product, and no combustion temp. 2. g C = (4.444)(12.01)/(44.01) = 1.213 g g H = (2.274)(2)(1.01) / 18.02 = .255 g 4.083- 1.468 = 2.615 g Pb/207.2 = .01262 mol Pb .1010 mol C -> 8 .2524 mol H -> 20 .01262 mol Pb -> 1 Is this correct? C8H20Pb