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What is the freezing point of a solution prepared by adding 264g of copper(ii) sulfate to 4 liters of water? The freezing point
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E1=E2 E1=(ks^2)/2 E2=mgh+(mv^2)/2 (ks^2)/2=mgh+(mv^2)/2 2*[(ks^2)/2-mgh]/m=v^2 sq[(ks^2-2mgh)/m]=v