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Bobz
Questions (4)
Given these standard reduction potentials at 25oC:
Cr3+ + e- -> Cr2+ (E1^o = -0.407V) Cr2+ + 2e- -> Cr(s) (E2^o = -0.913V)
4 answers
10,536 views
A solution prepared by mixing 16.7 mL of 0.760 M NaCl and 16.7 mL of 0.760 M KI was titrated with 0.380 M AgNO3 in a cell
1 answer
1,128 views
What would the units of the rate constant k be in a second order equation if rate was measured in mol/(L x s)and all
1 answer
549 views
Consider the following two thermochemical equations
N2+2.5O2-> N2O5(s) Delta H=xkJ N2+2.5O2-> N2O5(g) Delta H=ykJ The enthalpy
6 answers
2,325 views
Answers (3)
Thanks for the help! But I'm curious - why multiply E2 by 2, and then divide the answer by 3?
So it's C
Look this is what i did You multiply the first reaction by -1 so you have -x for the reactant (since its what you started with) and you have y for the product (since it makes a gas) So enthalpy change is Delta H=>H(products)- H(reactants) which means its