Bobpursley
This page lists questions and answers that were posted by visitors named Bobpursley.
Questions
The following questions were asked by visitors named Bobpursley.
Answers
The following answers were posted by visitors named Bobpursley.
It could be any of those: it depends on what you say. My guess is observation.
18 years ago
multiply both sides of the equation by 4PI. 2x+2 -2x=0 2=0 There is no value of x that can satisfy the equation.
18 years ago
What do you want to know about it?
18 years ago
Test it. if x=-6 the distance is 7. abs(x+7)=abs (-6+7)= abs (1)=1 You are correct
18 years ago
I will be happy to critique your thinking.
18 years ago
I don't know if there are only five. I have friends in biophysics, astrophysics, astronomy, high energy physics, condensed matter physics, nuclear energy, and physics education. Most engineering is applied physics.
18 years ago
It depends on what you want to do. Please try to be more specific.
18 years ago
The problem is much simpler than you are doing. Due to symettry, each side is supporting half the weight (1/2 mg= 2.5g) Now, using your angles SinTheta=2.5g/Tension Now substitute for sintheta, 2/sqrt(104) and solve for tension
18 years ago
Shelby: 20 can be represented by two factors, 4,5 16 can be represented by two factors, 8,2 What about 18? 14? Start with four and work up, see if you can find two factors of each number. The numbers are called factors.
18 years ago
assume the charges don't move. Work this as a vector problem. Find the force S due to the center charge and the N charge, and the Force E due to the center charge and the E charge. Add those as vectors
18 years ago
one ml= one cm^3. (100cm)^3 = (1m)^3 (10^2cm)^3=1m^3 10^6 cm^3=1m^3 1cm^3=10^-6 m^3
18 years ago
No. It means 548ml equals 548*10^-6 m^3 1ml=1cm^3=10^-6m^3
18 years ago
Tareyton. THe man would rather fight than switch. This was ran several years, and had sometimes women with black eyes. Of course, it turned out, they would rather get cancer than quit.
16 years ago