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We convert $n$ to base $10$. The base $7$ expression implies that $n = 49A + 7B + C$, and the base $11$ expression implies that $n = 121C + 11B + A$. Setting the two expressions equal to each other yields that$$n = 49A + 7B + C = 121C + 11B + A
1. A 2. D 3. C 4. B 100%
