Answers by visitors named: Bernd

x=8, δ=0.03 x=μ+zδ μ=x-zδ You have to find the mean that makes the range of 0oz to 8oz equal to 0.99 or the 99th percentile (because everything above 8oz should occur only in 1% of the time). You can look up the z-value for 0.99 in a Standard Normal Distribution table. z=2.32 μ=8-2.32*0.03=7.93 You get a mean of 7.93oz.