Ask a New Question
Search
Questions and answers by
Benjamin inyang edet
Answers (2)
L=0.1m R= 0.5/2=0.25×10^4 A= πr^2=22/7×(2.5×10^4)^2 P= AL/R= 3.14×25000= 78500/2 =39250 =3.93×10^7 ohm - metre
What is the resistivity of a cylindrical material wire whose 1.0m length a resistance of 2.0 ohms? The diameter of the wire is 0.5mm. Solution Length= 1.0m Resistance= 2.0 ohms Diameter= 0.5mm L= 0.1m R= 0.5/2=0.25=2.5×10^4 A= πr^2=22/7×(2.5×10^4)^2
