Questions and answers by

Bassam

Answers (1)

𝐶𝐻𝐶𝑙 = 1.18 ×103 𝑔 𝑟𝑒𝑎𝑔𝑒𝑛𝑡 𝐿 𝑟𝑒𝑎𝑔𝑒𝑛𝑡 × 37 𝑔 𝐻𝐶𝑙 100 𝑔 𝑟𝑒𝑎𝑔𝑒𝑛𝑡 × 1 𝑚𝑜𝑙 𝐻𝐶𝑙 36.5 𝑔 𝐻𝐶𝑙 = 12 𝑀 The number of moles HCl required

Ask a New Question