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Bartholomew
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A neutron collides elastically with a helium nucleus (at rest initially) whose mass is four times that of the neutron. The
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A bullet of mass 1.9×10−3 kg embeds itself in a wooden block with mass 0.987 kg, which then compresses a spring (k = 120 N/m)
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#1. Ten Christmas lights are connected in series and plugged into a 120 V wall outlet. Each light is identical and can be
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A 5 kg mass is thrown up with a velocity of 4 m/s from a height of 30 m onto a spring with a relaxed length of 10 m, and a
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A 5 kg mass is thrown up with a velocity of 4 m/s from a height of 30 m onto a spring with a relaxed length of 10 m, and a
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A 50 kg block is on a 30 degree incline. The coefficient of friction between the block and the incline 0.05. If it is given an
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Answers (5)
I plugged in my value for x, but both sides of the equation had different values, so I think I have the wrong value for x. How do I solve 200x^2-49x+490?
There are 3 feet in a yard. Square yards to get square yards.
(V2^2)=(Vi)^2+2ad 0=16-19.6d -16=-19.6d d=0.816 m + 30 m = 30.816 meters above the ground mgh = mgh + 1/2kx^2 = (5 kg)(9.8 m/s^2)(30.816) = 200x^2-49x+490 x=2.75 m mgh=1/2kx^2+mgh+1/2mv^2 (5)(9.8)(30.186)=1/2(400)(0.3)^2+(5)(9.8)(9.7)+1/2(5v^2) v=20.17 m/s
Sorry about the lines, I was expecting it to look like this: img517.imageshack.us/img517/9280/picture1in2.png
ANSWER A = 133.333333 B = 33.3333333 C = 13.3333333 WORK A = 4B C = B-20 A + B + C = 180 | | | | (4B) + B (B-20) = 180 \ | / \ | / \ | / \ | / \ | / \|/ 6B - 20 = 180 B = 33.33333 ^ A is 4 times that C is 20 less than that
