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Bamiduro
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A spring 20cm long is stretched to 25cm by a load of 50N.What will be its length when stretched by 100N assuming that the
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E=25-20=5.so,f=50N/5cm=10N/cm new length =(original length +E)=20cm+10cm=30cm E=(25cm-20cm)=5cm so,f=50N/5cm=10N/cm E=100N/10N/cm=10cm new length=(original length+E)=20cm+10cm=30cm