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Az5722
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Solution 1: [asy] unitsize(1 cm); pair E, F, G, H, M, N, P, Q; E = (1,2); F = (5,2); G = (4,0); H = (0,0); M = (E + F)/2; N = (E + H)/2; P = extension(F,H,G,M); Q = extension(F,H,G,N); draw(E--F--G--H--cycle); draw(F--H); draw(G--M); draw(G--N);
AoPS, please. Don't yell at people for using this website like they're supposed to, then asking questions yourself. That's just hypocritical.
I'm 6 years too late, but... 1. Let the median of the trapezoid be $m$. Then by the formula for the area of the trapezoid, \[5m = 60,\]so $m = \boxed{12}$. (The fact that one base is 4 units longer than the other is irrelevant.) 2. (This is written using
