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Avogadro
Answers (1)
pH=11.23 [H+]= 10^(-11.23)=5.888*10^-12 (1*10^-14)/(5.888*10^-12)=[OH]=.001698M/L .001698/2= .0008491 moles/.5L .0008491*40(molar mass of NaOH)=.033964*1000= 33.96mg
