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A daring stunt woman sitting on a tree limb
wishes to drop vertically onto a horse galloping under the tree. The constant speed
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Answers (9)
Well, you could take 1/6 of 3 3/5 first convert 3 3/5 into an improper fraction 3 = 15/5 so 15/5 + 3/5 = 18/5 (= 3 3/5) now multiply 18/5 * 1/6 this should give you 1/6 of the distance. remember when you multiply fractions you just multiply the numerators
The answer is B, because all your other sentences use a conjunction to connect the independent clauses that could be sentences, but B doesn't do that. It just goes on without a conjunction or punctuation to make it into another sentence.
It's a system of equations problem. Just represent the values with different expressions as they relate. givens: 28 animals total number of piranhas = 1 more than turtles number of piranhas = 2 less than number of beta fish let x = number of piranhas
you just add coefficients to the reactants or products on either side to make sure that the same number of elements are present on one side as there are on the other. you can google or search balance chemical equations on the internet or google khan
i believe it's kinetic energy, once the car stops it may transfer that energy to the ground or even a rock causing it to move; therefore, producing movement.
create a proportion to find out how much one mole weighs .347moles = 39.00g 1 mole = ? now just cross multiply and solve whatever you get for the weight you can match it to one on the periodic table with that molar mass since the mass listed on the
just remember 10^5 is equal to 100,000 and this is only for one second. if you multiply 100,000 by 10 you will get how many calculations it can make in 10 seconds.
Ok how bout if you equate the number of movies each store sold as x and then multiply it by how much it costs to rent a movie at each store. Set up two equations with the member fee included into the equation,one for Store A (use y to represent the total
just use this equation and remember that initial velocity is zero because the car began at rest (final velocity)^2 = (initial velocity)^2 + 2*(acceleration)*(displacement) you may need to rearrange the equation to say that ((final veocity)^2-(initial
