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Arpita
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find the point(s) of inflection on the function f(x)= 10/x + 10/x^2
Sorry this one's easier to read. 1.. Call the point where d intersects AB point C. 2.. Let CB equal x. 3.. cot(14)= (30-x)/d cot(34)= x/d 4.. cot(14)= (30/d)- (x/d) cot(14)= (30/d)- cot(34) cot(14)+ cot(34)= (30/d) d(cot14+ cot34)= 30 d = 30/ (cot14+
1. Call the point where d intersects AB point C. 2. Let CB equal x. 3. cot(14)= (30-x)/d cot(34)= x/d 4. cot(14)= (30/d)- (x/d) cot(14)= (30/d)- cot(34) cot(14)+ cot(34)= (30/d) d(cot14+ cot34)= 30 d = 30/ (cot14+ cot34) d = 5.46 km
