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Arash
Answers (1)
The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f'(x) = -sin(x) f''(x) = -cos(x) f'''(x) =
