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Water is being poured into a conical tank that has a height of 4.5m and an upper radius of 2.7m. If the height of the water is
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thanks oobleck, i ended up doing dV/dt = 3pi/25 *3h^2 * dh/dt -> 3pi/25 * 3(1.24)^2 * (0.115m/s) = 0.20m^3/s. I like ur way of writing out ``dv/dt = π/3 (2rh dr/dt + r^2 dh/dt)``. Thanks for your input.
