Ask a New Question
Search
Questions and answers by
Anusha Ghimire
Answers (1)
2tan3x cos2x + 1 = tan3x + 2cos2x Or ,2tan3x cos2x - tan3x - 2cos2x + 1 = 0 Or, tan3x ( 2cos2x - 1) - ( 2cos2x- 1) = 0 Or , (tan3x-1) (2cos2x-1) =0 Either, tan3x-1=0. Or, 2cos2x= 1 Or, tan3x = 1. Or,cos 2x= cos 1/2 Or, tan 3x=tan 45 Or, 2x=2nπ+_ π/3 Or,
