Anuradha

I have a sum which I share with u.. Perimeter of rectangle is 2.4m less than (2/5) of perimeter of square. If the perimeter of square is 40m then find the length & breadth.. Given breadth is (1/3) of the length.. I have also a solution which I wnna be pos...

A similar thing happened to me !!!!! thanks for the help

And Btw - for me we had to find the emperical formula for CuSO4 . H2O and after doing the experiment I found out that the value that i got was CuSO4 . 6H2o when the correct answer should be CuS04 . H2o

Perimeter of rectangle= 2/5 ( perimeter of square) So, ACCORDING TO QUESTION, 2(L+L/3)= (2/5*40)-2.4 2(3L+L)/3= 16-2.4 2*4L/3=13.6 L=(13.6*3)/8*10 L=5.1m B=5.1/3= 1.7m (answer)

E=nhc/lamda >1.5= 3*10^18 * 6.626*10^-34 * 3*10^8/ lamda(wavelength) Therefore wavelength =3.973*10^-7