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Anonn
Answers (3)
1. I'm not sure. 2. B 3. B 4. B 5. C
This is a whole test.
200 cal/g * 1000g/kg * 2.4kg = 480000 cal The latent heat required to turn 0C water to 0C ice is 80cal/g 480000 / 80 = 6000g or 6.0kg
