Ask a New Question
Search
Questions and answers by
Ann Hiro
Answers (8)
F = MA, right? Just mix in a cos Θ to calculate effective force (42N x cos 22° = 38.94172N), and solve. 38.94172 = 7.6A A = 38.94172 / 7.6 A = 5.123911m/s^2
a) Acceleration due to gravity is a 'constant' force (generally 9.8m/s^2), so in both cases, she will be accelerating at 9.8m/s^2 b) Sorry, I don't remember the formulas, so I'm using calc for this (velocity is the integral of acceleration, position is the
I knew I was missing something... On the last bit, if passengers could take both of the snacks, AND elect to take nothing from any of the three categories, you get 156 combinations (13 x 4 x 3), so THAT would indeed work...
The first two questions seem the exact same, oddly; perhaps I'm misunderstanding, but going on the assumption that I'm not... There are 48 different combinations of grub (12 x 2 x 2), so the first two are 'no'. When the passengers could elect to take both
whoa- helps if you do your algebra right, which I didn't; D=x/A... Ignore my previous post =-/
is CD (4/3)x, or 4/(3x)? From AD = x, we can say that D = A/x, and plug that into CD = 4/3x, giving us (A/x)C = 4/3x AC = 4x/3x = 4/3 (if CD = 4/(3x)) ---------------------------------- AC = 4x^2/3 (if CD = (4/3)x)
Yes, so long as the largest side is not larger than the sum of the other 3 sides (i.e. 20, 2, 2, 2 wouldn't work).
primes are numbers which are only divisible by 1 and itself. The primes between 1 and 50 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, and 47. Your job is to find a combination of these numbers which multiply to 50. Took me a while to figure it
