Angel Eyes

f(x)= -4(x+5)^2+3 The vertex is : -5,3 The line of symmetry is x= 3 The maximum/minimum value of f(x)= -5 Is the value of f(-5)=3, a minimum or maximum? Minimum Graphing would open from the bottom going up on the negative side.

Find the greatest common factor for the group of terms. -66a^2, 11a^5 11a^5

Ms. Sue...I understand how to get the sqrt of 420, but after that I get lost. So what you typed is not making sense in my head ..ughhh

420, so more or less I would have had to have found 2 numbers that equaled 420 when multiplied (which product means multiply 2 numbers)correct? So my first page would be 20 Second page would be 21

Thank you very much for your help. I appreciate it very much!

That's where I got lost was when I was trying to find the roots of the quadratic equation. I guess I just need more practice with these roots.

0.4 x 0.4 = 0.16 8.8 x 8.8 = 77.44 15 x 15 = 225

Joejoe can you possibly take a look at a problem I posted earlier under Math/Algebra ? I would greatly appreciate it!

So then I would end up with the ticket sales would peak 11 days after, and the number of tickets sold that day would be 63.4 Correct or No?

Although it says to round to the nearest integer. So this would actually be sales peak 11 days after, and the number of tickets sold would just be 63.

Ahhhh Thank you very much! I seem to get lost when it comes to the cleaning up the decimals & then trying to get the square root if it is in decimal form. I appreciate your help Reiny :)!

If I remember correctly ant. Good soil does contain, all of those. Without one of them; the soil wouldn't be that great of soil. You can check with one of the tutors, but I am thinking you are correct!

Okay. I had the vertex written in correctly. the line of symmetry & max function I had backwards for some unknown reason. The other 2 parts I had totally wrong. Thank you for checking this for me Reiny! I was leery at posting it until I had it checked. Go...

I put the vertex as (-5,3) and it is saying it was wrong...ughhhhhhhh.

You are very welcome! Glad I could help someone!!!! Good Job on that one! :)