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Angamba
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Let 2k,2k+2 and 2k+4 be three consecutive even integers. Then,their product 2k(2k+2)(2k+4)=8k(k+1)(k+2) Which is divisible by 8. But k,k+1,k+2 are three consecutive integers and the product of these three integers is divisible by 6. So,2k(2k+2)(2k+4) is
