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Andrew Blakely

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Well imagine the pipe, the diameter of the pipe is 2 inches.Those 2 inched are comprised of the empty part of the pipe and its thickness, which happens to be 3/16's of an inch thick. Now, a pipe has both a bottom and top thickness if you imagine the
I'm going to make the assumption that this is in vector unit notation and that this is a two dimensional problem. If particle P is moving 2.0m/s(i) + 4m/s(j) with respect to particle A then particle A should appear to be moving -2.0m/s(i) - 4.0m/s(j). This
Well, I'm not sure how to solve this with a formula but the cubed root of 64 happens to be 4. Maybe you could say x^3=64 thus x=(64)^(1/3). I'm sorry, honestly I've never solved for a cube by hand.
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To calculate the magnitude of the accelerations you can use the formula F=ma. The girl's acceleration is simply 5.55N / 38.5kg = a A in this instance is .14 m/s^2, I think.

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