Amone

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Questions

The following questions were asked by visitors named Amone.

In obtuse triangle PQR, P=51 degrees, p= 10cm, and the longest side, q=12cm.Draw the triangle and solve for Q to the nearest degree. I did, 10/sin 51=12/sin Q 10(sin Q)/10=12(sin 51)/10 Q= 2nd function sin 0.9325751 Q=68 degrees Q=180-68 Q=111 degrees
9 years ago

Answers

The following answers were posted by visitors named Amone.

But when I tried to prove this it seems right. What I did, Sin18(10)/(sin 51)=r 4=r Cos Law: 4x4=(10x10)+(12x12)-2(12)(10)cos 18 degrees 16=100+144-228.23 16=15.96
9 years ago
Isn't the Obtuse angle always opposite of the longest side? I'm confused, is there a big a misunderstanding on my side.
9 years ago